How do you solve #x/4 - 4/x=0#?

2 Answers

Answer:

Work backwards combine like terms and remove the fractions

Explanation:

The order of operations is PEMDAS in reverse it is PESADM

Start by removing the parenthesis a / divided symbol acts as a parenthesis so remove the division symbols like this

# 4x xx (x)/4 - 4x xx (4)/x = 4x xx 0 #

Dividing out the common terms gives

# x^2 - 16 = 0#

Work backwards by subtracting 16 from both sides

# x^2 - 16 +16 = 0 +16 #

This gives

# x^2 = 16 #

Taking the square root of both sides gives

# sqrt x^2 = sqrt 16#

Which gives and imaginary number

# x = (+/- )4 #

Jul 25, 2018

Add #4/x# to both sides

#=> x/4=4/x#

Cross multiply

#x^2=16#

Square root both sides

#x= \pm4#