How do you solve #(x+4)/-7 = -3#?

2 Answers
Nov 10, 2017

#x=17#

Explanation:

#"multiply both sides of the equation by "-7#

#cancel(-7)^1xx(x+4)/cancel(-7)^1=-7xx-3#

#rArrx+4=21#

#"subtract 4 from both sides"#

#xcancel(+4)cancel(-4)=21-4#

#rArrx=17" is the solution"#

Nov 10, 2017

Multiply both sides by #-7#
#(x+4)/cancel(-7) cancel(-7) = -3xx-7#
Minus into minus = plus
#x+4=21#
Subtract both sides by 4
#xcancel(+4) cancel (-4) = 21-4#
#x=17#