# How do you solve #(x + 5)(3x+1)=0#?

##### 1 Answer

#### Answer:

#### Explanation:

You can easily solve this equation by recognizing that the product of two terms is equal to zero if either one of those terms (or both, that's not the case here) is equal to **zero**.

In your case, the product of

#(x+5) = 0# or#(3x+1) = 0#

This means tha the two solutions to your equation will be

and

If, for some reason, you'd want to complicate things a little, you could rewrite your equation in quadratic form

and use the *quadratic formula* to solve for the two solutions.

#color(blue)(x_(1,2) = (_b +- sqrt(b^2 - 4ac))/(2a)#

In your case, you have

Once again, you'd get

and