# How do you solve #x- 5= 3x + 2#?

##### 1 Answer

Dec 12, 2016

#### Explanation:

To solve questions like these, we take all the variable terms, which are those terms with an **not having a fixed value** (*variable*) to one side.

If we Add, Subtract, Multiply or Divide the same quantity from each side, the equation remains unaffected.

So, to bring all variable terms to one side, subtract

#x - x - 5 = 3x - x - 2#

#=> -5 = 2x + 2#

Next, take all the *constant* terms **(those terms having a fixed value)** to the other side by subtracting 2 from each side to get

#-5 - 2 = 2x + 2 - 2#

#=> -7 = 2x#

Now, divide both sides by 2 to leave only

#-7/2 = x# #color(white)("XXX") or # #color(white)("XXX")# #x = -7/2 = -3 1/2#