How do you solve x^5-5x^3+4x=0?

1 Answer
Oct 23, 2015

x=0, x=1, x=2, x=-1, and x=-2

Explanation:

Start off by factoring out an x as follows

x(x^4-5x^2+4)=0

We can factor x^4-5x^2+4

Doing so we have

x(x^2-4)(x^2-1)=0

So in order for this to be equal to zero

x=0

OR

x^2-4=0

OR

x^2-1=0

Well x=0

x^2=4

x=+-sqrt(4)=+-2

x^2=1

x=+-sqrt(1)=+-1