How do you solve #x² = 5x + 10# using the quadratic formula?

1 Answer
Mar 16, 2018

Answer:

Read below.

Explanation:

Let's put the variables and the numbers on one side.

We have:

#x^2-5x-10=0# Since this quadratic equation is in the form #ax^2+bx+c=0#, #a=1#, #b=-5# , and #c=-10#

The quadratic formula states that:

#x=(-b+-sqrt(b^2-4(a)(c)))/(2a)# Plug in the values.

#=>x=(-(-5)+-sqrt((-5)^2-4(1)(-10)))/(2*1)#

#=>x=(5+-sqrt(25+40))/2#

#=>x=(5+-sqrt(65))/2#

#=>x=(5+-sqrt(65))/2#

Your two answers would be #(5-sqrt(65))/2# and #(5+sqrt(65))/2#