How do you solve #x - 6 = -x^2#?
1 Answer
Mar 29, 2018
Explanation:
#"express the equation in "color(blue)"standard form"#
#rArrx^2+x-6=0larrcolor(blue)"in standard form"#
#"the factors of - 6 which sum to + 1 are + 3 and - 2"#
#rArr(x+3)(x-2)=0#
#"equate each factor to zero and solve for x"#
#x+3=0rArrx=-3#
#x-2=0rArrx=2#
