Question

How do you solve `(x - 9)^2 = 1`?

Answer 1

If a number to the square is `1`, that number is either `1` or `-1`

Explanation:

Thus if `(x-9)^2=1` we know that either `(x-9)=1` or `(x-9)=-1`.

Hence we have either `x=10` or `x=8`