How do you solve (x+a)^2-b^2 = 0 by factoring?

Aug 28, 2015

color(green)(x = -a - b or x = -a + b

Explanation:

We use the identity color(blue)(p^2 - q^2 = (p+q)*(p-q)

Here $p = x + a$ and $q = b$

Hence ${\left(x + a\right)}^{2} - {b}^{2} = 0$ can be written as :

$\left(x + a + b\right) \left(x + a - b\right) = 0$

This implies that:

$x + a + b = 0 \mathmr{and} x + a - b = 0$

color(green)(x = -a - b or x = -a + b