How do you solve #x-\frac{15}{x}=2#?
1 Answer
Jun 4, 2018
Explanation:
#"multiply all terms by "x#
#x^2-15=2x#
#x^2-2x-15=0larrcolor(blue)"in standard form"#
#"the factors of - 15 which sum to - 2 are - 5 and + 3"#
#(x-5)(x+3)=0#
#"equate each factor to zero and solve for x"#
#x+3=0rArrx=-3#
#x-5=0rArrx=5#
