How do you solve -x=x^2?

Jul 7, 2016

$x = 0 \mathmr{and} x = - 1$

Explanation:

Add $x$ to both sides.

${x}^{2} + x = 0$

Factor

$x \left(x + 1\right) = 0$

In order to satisfy the equation, the left hand side must equal zero. This means that either $x = 0$ or $x + 1 = 0$

$\implies x = 0 \mathmr{and} x = - 1$