How do you solve #x(x^2 + 16) = 0#?

2 Answers
Apr 27, 2018

Answer:

#x# = 0

Explanation:

In multiplication, the only way to have #0# as a product is to multiply a number(s) by at least one #0#. Using this property of multiplication, we know that at least one of the terms is equal to #0#:

#x# = 0 | #x^2# + 16 = 0

To solve for the second term, first subtract #16# from both sides of the equation, giving us:

#x^2# = -16

However, there is no real number that can be squared to equal a number lower than #0#, so there is no real solution for the second term.

Apr 27, 2018

Answer:

Shown below

Explanation:

We know if #ab=0 #

Then #a= 0 # or # b = 0 #

#color(red)(=> x = 0 #

#=> x^2 + 16 = 0 #

#=> x^2 = -16 #

#color(blue)(=> x = pm 4i #

If #x in RR -> x = { 0 } #

if #x in CC -> x = { 0 , 4i , -4i } #