Question

How do you solve `x² + x = 6`?

Answer 1

`x=-3, 2`

Explanation:

`x^2+x=6` => Subtract 6 from both sides:
`x^2+x-6=0` => `x=3x-2x`:
`x^2+3x-2x-6=0` => factor by grouping:
`x(x+3)-2(x+3)=0`
`(x+3)(x-2)=0`
The Zero Product Property: if ab=0, then either a=0  or  b=0, or both.
`x+3=0` => `x=-3`
`x-2=0` => `x=2`