How do you solve #x + y = 6# and #x = y + 2#?

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Answer 1 · 2018-06-03T14:52:03

#x=4,y=2#

Substitute the second equation into the first equation to get:

#(y+2)+y=6#

#y+2+y=6#

#2y+2=6#

#2y=4#

#y=4/2=2#

Now, plug in #y=2# in either equations to solve for #x#. I'll choose the latter one.

#x=2+2#

#x=4#

So, the solution to the system of equations is:

#=>[(x=4),(y=2)]#