How do you solve $x= -y-6$ and $x=y-3$ using substitution?

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Answer 1 · 2016-03-07T07:21:12

Solution is $x=-9/2$ and $y=-3/2$

To solve system of linear equation in two variables using substitution, one substitutes value of one variable from one equation in another equation.

In equations $x=−y−6$ and $x=y−3$ , let us substitute value of $x$ (which is $y-3$ into first equation which gives us

$y−3=−y−6$ or by transposing similar terms $y+y=-6+3$ or

$2y=-3$ or $y=-3/2$ and now putting this in $x=-3/2−3$ or

$x=-9/2$

Hence solution is $x=-9/2$ and $y=-3/2$

How do you solve x= -y-6x= -y-6 and x=y-3x=y-3 using substitution?