# How do you solve x= -y-6 and x=y-3 using substitution?

Mar 7, 2016

Solution is $x = - \frac{9}{2}$ and $y = - \frac{3}{2}$

#### Explanation:

To solve system of linear equation in two variables using substitution, one substitutes value of one variable from one equation in another equation.

In equations x=−y−6 and x=y−3, let us substitute value of $x$ (which is $y - 3$ into first equation which gives us

y−3=−y−6 or by transposing similar terms $y + y = - 6 + 3$ or

$2 y = - 3$ or $y = - \frac{3}{2}$ and now putting this in x=-3/2−3 or

$x = - \frac{9}{2}$

Hence solution is $x = - \frac{9}{2}$ and $y = - \frac{3}{2}$