How do you solve xe^(2x)=5e^(2x)xe2x=5e2x?

1 Answer
May 15, 2015

You have an equation where both sides share a common factor: e^(2x)e2x.

The simplest way is to eliminate such terms. You can think this in two different possible ways, but both end up doing the same for you: solving your equation to xx.

First: you can divide both sides of the equation by e^(2x)e2x, as follows:

(x*cancel(e^(2x)))/cancel(e^(2x)) = (5*cancel(e^(2x)))/cancel(e^(2x))

This will leave you with the very result: x = 5.

Another possible way of thinking the problem is to pass the left e^(2x) to the right side, now dividing this side, in order to isolate x, as follows:

x = (5*cancel(e^(2x)))/cancel(e^(2x))

You choose which line of thought you prefer, but the different solutions will lead you to the same answer!