# How do you solve y^2 + 12y + 11 = 0?

Jun 5, 2016

$y = - 1 \mathmr{and} y = - 11$
$y = - 6 \pm \sqrt{{6}^{2} - 11}$
$y = - 6 \pm \sqrt{25}$
$y = - 6 \pm 5$
$y = - 1 \mathmr{and} y = - 11$