How do you solve $y = 2x – 4$ and $7x – 5y = 14$ using substitution?

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Answer 1 · 2016-07-31T06:00:50

$x=2; y=0$

Since $y=2x-4$ , let's substitute the expression $2x-4$ in y in the second equation:

$7x-5(2x-4)=14$

$7x-10x+20=14$

$-3x=14-20$

$-3x=-6$

$x=2$

Now let's substitute the value 2 in x in the first equation:

$y=2(2)-4=0$

How do you solve y = 2x – 4y = 2x – 4 and 7x – 5y = 147x – 5y = 14 using substitution?