How do you solve #(y+3)/3 =( 3y-5)/2#? Algebra Rational Equations and Functions Clearing Denominators in Rational Equations 1 Answer Don't Memorise Sep 8, 2015 #color(blue)(y=3# Explanation: #(y+3)/color(blue)(3) =(3y-5)/color(blue)(2# Cross multiplying #(y+3) * color(blue)(2) =(3y-5) *color(blue)(3# #2y +6 = 9y -15# #6 +15 = 9y - 2y# #21 = 7y# #y = 21/7# #color(blue)(y=3# Answer link Related questions What is Clearing Denominators in Rational Equations? How do you solve rational expressions by multiplying by the least common multiple? How do you solve #5x-\frac{1}{x}=4#? How do you solve #-3 + \frac{1}{x+1}=\frac{2}{x}# by finding the least common multiple? What is the least common multiple for #\frac{x}{x-2}+\frac{x}{x+3}=\frac{1}{x^2+x-6}# and how do... How do you solve #\frac{x}{x^2-36}+\frac{1}{x-6}=\frac{1}{x+6}#? How do you solve by clearing the denominator of #3/x+2/x^2=4#? How do you solve #2/(x^2+2x+1)-3/(x+1)=4#? How do you solve equations with rational expressions #1/x+2/x=10#? How do you solve for y in #(y+5)/ 2 - y/3 =1#? See all questions in Clearing Denominators in Rational Equations Impact of this question 1404 views around the world You can reuse this answer Creative Commons License