# How do you solve y+3/4=1/3?

$4 y + \frac{3}{4} = \frac{1}{3} \implies 3 \left(4 y + 3\right) = 4 \implies 12 y + 9 = 4 \implies 12 y = - 5 \implies y = - \frac{5}{12}$
so having $y = - \frac{5}{12}$ we can solve the problem  y+3/4=1/3=> -5/12+3/4=1/3=>-5/12+9/12=4/12=>4/12=4/12 which is true