How do you solve #y/3=48/9#?

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Answer 1 · 2017-02-13T12:51:43

See the entire solution process below:

Multiply each side of the equation by #color(red)(3)# to solve for #y# while keeping the equation balanced:

#color(red)(3) xx y/3 = color(red)(3) xx 48/9#

#cancel(color(red)(3)) xx y/color(red)(cancel(color(black)(3))) = cancel(color(red)(3)) xx 48/(color(red)(cancel(color(black)(9))) 3)#

#y = 48/3#

#y = 16#

and

#16/3 = 48/9#