# How do you solve y = 3x^2 − 2x − 5 ?

Sep 7, 2017

$3 {x}^{2} - 2 x - 5 = 0$

$3 {x}^{2} + 3 x - 5 x - 5 = 0$

$3 x \cdot \left(x + 1\right) - 5 \cdot \left(x + 1\right) = 0$

$\left(x + 1\right) \cdot \left(3 x - 5\right) = 0$

Thus, $x 1 = - 1$ and $x 2 = \frac{5}{3}$.

#### Explanation:

I used distribution and collection rules of polynomials.