Question

How do you solve `y = 3x^2 − 2x − 5`?

Answer 1

`3x^2-2x-5=0`

`3x^2+3x-5x-5=0`

`3x*(x+1)-5*(x+1)=0`

`(x+1)*(3x-5)=0`

Thus, `x1=-1` and `x2=5/3`.

Explanation:

I used distribution and collection rules of polynomials.