# How do you solve #y=4x-3, 2y-3x=4#?

##### 1 Answer

Jan 11, 2017

#### Explanation:

Since we are given

#y=4x-3# we can substitute this into the other equation and solve for x.

#rArr2(color(red)(4x-3))-3x=4# distributing.

#8x-6-3x=4# add 6 to both sides and simplify.

#5xcancel(-6)cancel(+6)=4+6#

#rArr5x=10# To solve for x, divide both sides by 5

#(cancel(5) x)/cancel(5)=10/5rArrx=2# We can now substitute x = 2 into y = 4x - 3 to find y.

#x=2toy=(4xx2)-3=8-3=5#