How do you solve #y = log^3(78.5)#?
1 Answer
Feb 8, 2016
Explanation:
There is no way to simplify this, other than writing this as
#y=log^3(78.5)=log(78.5)xxlog(78.5)xxlog(78.5)#
Note that this is different than the other logarithm rules:
#log(a^b)=bxxlog(a)#
#log(a)+log(b)=log(ab)#
However, the only way to find this is the use a calculator:
#y=log(78.5)xxlog(78.5)xxlog(78.5)=color(blue)(6.80358827392#