Question

How do you solve `y=(x+2)^2-5`?

Answer 1

x= -2`+-sqrt5`

Explanation:

Solving the given equation would imply finding the roots of the quadratic on the right side. This can be done by making y=0 and solving for x

`(x+2)^2 -5=0`

`(x+2)^2=5`

x+2= `+- sqrt5`

x= -2`+- sqrt5`