How do you solve #y = x^2 + 3x + 2#?

1 Answer
Alan P.
Jul 8, 2015

It depends on what you want to solve for.
#color(white)("XXXX")#the y intercept #= 2#
#color(white)("XXXX")#the x intercepts #=-1# and #-2#
#color(white)("XXXX")#the vertex = #(-3/2,1/4)#

Explanation:

You are given the generalized solution for #y#.

If you want a different solution then what kind of solution you want needs to be specified.

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