# How do you solve y = x^2 + 3x + 2?

Jul 8, 2015

$\textcolor{w h i t e}{\text{XXXX}}$the y intercept $= 2$
$\textcolor{w h i t e}{\text{XXXX}}$the x intercepts $= - 1$ and $- 2$
$\textcolor{w h i t e}{\text{XXXX}}$the vertex = $\left(- \frac{3}{2} , \frac{1}{4}\right)$
You are given the generalized solution for $y$.