# How do you solve  y = x^2 - 4x + 4 using the quadratic formula?

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#### Explanation

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#### Explanation:

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1
Mar 9, 2018

See a solution process below:

#### Explanation:

For $\textcolor{red}{a} {x}^{2} + \textcolor{b l u e}{b} x + \textcolor{g r e e n}{c} = 0$, the values of $x$ which are the solutions to the equation are given by:

$x = \frac{- \textcolor{b l u e}{b} \pm \sqrt{{\textcolor{b l u e}{b}}^{2} - \left(4 \textcolor{red}{a} \textcolor{g r e e n}{c}\right)}}{2 \cdot \textcolor{red}{a}}$

Substituting:

$\textcolor{red}{1}$ for $\textcolor{red}{a}$

$\textcolor{b l u e}{- 4}$ for $\textcolor{b l u e}{b}$

$\textcolor{g r e e n}{4}$ for $\textcolor{g r e e n}{c}$ gives:

$x = \frac{- \textcolor{b l u e}{- 4} \pm \sqrt{{\textcolor{b l u e}{- 4}}^{2} - \left(4 \cdot \textcolor{red}{1} \cdot \textcolor{g r e e n}{4}\right)}}{2 \cdot \textcolor{red}{1}}$

$x = \frac{4 \pm \sqrt{16 - 16}}{2}$

$x = \frac{4 \pm 0}{2}$

$x = \frac{4}{2}$

$x = 2$

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