How do you solve #y=x^2-6x-1# using the quadratic formula?

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Answer 1 · 2018-08-07T08:55:46

#x=3+-sqrt10#

#x=(-b+-sqrt(b^2-4ac))/(2a)#
where your quadratic equation is #y=ax^2+bx+c#

#x=(6+-sqrt((-6)^2-4(1)(-1)))/(2times1)#

#x=(6+-sqrt(36+4))/2#

#x=(6+-sqrt40)/2#

#x=(6+-2sqrt10)/2#

#x=3+-sqrt10#