How do you solve #y = x^2 - 6x + 8 = 0# using the quadratic formula?

Question

2895 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-09T20:54:00

Use the coefficients with the formula, and you will find that #x={2,4}#

The Quadratic Formula is written as follows:

#x=(-b+-sqrt(b^2-4ac))/(2a)#

Where the quadratic equation used looks like this:

#ax^2+bx+c=0#

Using this pattern, we can see the following:

#a=1#
#b=-6#
#c=8#

Let's plug these numbers into the formula:

#x=(-(-6)+-sqrt((-6)^2-4(1)(8)))/(2(1))#

#x=(6+-sqrt(36-32))/2#

#x=(6+-sqrt(4))/2=(6+-2)/2=3+-1#

#x={(3-1),(3+1)}#

#color(green)(x={2,4}#