Question

How do you solve `z+4(2z+3)=15`?

Answer 1

See the entire solution process below:

Explanation:

First, expand the terms in parenthesis on the left side of the equation:

`z + (4 xx 2z) + (4 xx 3) = 15`

`z + 8z + 12 = 15`

Next, combine like terms on the left side of the equation:

`1z + 8z + 12 = 15`

`(1 + 8)z + 12 = 15`

`9z + 12 = 15`

Then, subtract `color(red)(12)` from each side of the equation to isolate the `z` term while keeping the equation balanced:

`9z + 12 - color(red)(12) = 15 - color(red)(12)`

`9z + 0 = 3`

`9z = 3`

Now, divide each side of the equation by `color(red)(9)` to solve for `z` while keeping the equation balanced:

`(9z)/color(red)(9) = 3/color(red)(9)`

`(color(red)(cancel(color(black)(9)))z)/cancel(color(red)(9)) = 1/3`

`z = 1/3`