# How do you subtract 10-6 3/8?

##### 1 Answer
Jan 7, 2017

See full process below:

#### Explanation:

First, we need to convert the mixed fraction to an improper fraction. We do this by multiplying the integer portion of the mixed fraction by the appropriate form of $1$ and then adding this result to the fraction portion of the improper fraction:

$10 - \left(\left(\frac{8}{8} \times 6\right) + \frac{3}{8}\right) \to$

$10 - \left(\frac{48}{8} + \frac{3}{8}\right)$

$10 - \frac{51}{8}$

Next we need to get the two terms over a common denominator (8 in this case) so we can subtract the fractions. We do this by multiplying $10$ by the appropriate form of $1$ again.

$\left(\frac{8}{8} \times 10\right) - \frac{51}{8}$

$\frac{80}{8} - \frac{51}{8}$

$\frac{80 - 51}{8}$

$\frac{29}{8}$

Or

$\frac{24 + 5}{8} = \frac{24}{8} + \frac{5}{8} = 3 + \frac{5}{8} = 3 \frac{5}{8}$