How do you subtract # b/(b-5) - 2/(b+3) #?
1 Answer
Aug 24, 2017
#(b^2+b+10)/((b-5)(b+3))#
Explanation:
Given -
#b/(b-5)-2/(b+3)#
Find the common denominator. it is -
#(b-5)(b+3)#
Then
#((b+3)b-(b-5)2)/((b-5)(b+3))#
#((b^2+3b)-(2b-10))/((b-5)(b+3))#
#(b^2+3b-2b+10)/((b-5)(b+3))#
#(b^2+b+10)/((b-5)(b+3))#
