Question

How do you translate the graph of `y=sin(x-pi/3)`?

Answer 1

Below

Explanation:

`y=sin(x-pi/3)` is your `y=sinx` graph but shifted to the right by `pi/3` units

`y=asin(nx+b)` is the general form
`a` is the amplitude
`n` is used to find the period of the function
`b` is the shift to left or right

Therefore, wtih reference to the general form, `y=sin(x-pi/3` has an amplitude of 1, a shift to the right by `pi/3` units.

The period is found using this equation
`T=(2pi)/n`
`T=(2pi)/1`
`T=2pi`
That means the graph finishes one cycle in `2pi`

Below is `y=sinx`

graph{sinx [-10, 10, -5, 5]}

Below is `y=sin(x-pi/3)`. Notice that it is exactly the graph `y=sinx` but moved to the right by `pi/3` units

graph{sin(x-pi/3) [-10, 10, -5, 5]}