# How do you turn a standard form to vertex form  y=x^2-2x+1?

Jun 12, 2018

${\left(x - 1\right)}^{2}$

#### Explanation:

${x}^{2} - 2 x + 1 = {x}^{2} - 2 x + {1}^{2}$
so${x}^{2} - 2 x + 1 = {\left(x - 1\right)}^{2}$ $0 \cdot 2 = 0$
$\left(x - 1\right)$ must be equal to $0$
so $x = 1$

Jun 12, 2018

complete the square

${\left(x - 1\right)}^{2} + 1 - 1$

${\left(x - 1\right)}^{2}$

Vertex (1,0)