How do you turn a standard form to vertex form # y=x^2-2x+1#? Precalculus Geometry of a Parabola Standard Form of the Equation 2 Answers Linda H. Jun 12, 2018 Answer: #(x-1)^2# Explanation: #x^2-2x+1=x^2-2x+1^2# so#x^2-2x+1=(x-1)^2# #0*2=0# #(x-1)# must be equal to #0# so #x= 1# Mark D. Jun 12, 2018 complete the square #(x-1)^2+1-1# #(x-1)^2# Vertex (1,0) Related questions How do I find the standard equation of a parabola? How do I find the standard equation of a parabola given 3 points? How do I find the focus of the parabola represented by #y=2x^2-8x+9#? What is the standard form of the equation for a parabola? In the standard form of the equation for a parabola, what is represented by #a#? What is the directrix of a parabola? How do I find the focus of the parabola with the equation #y=1/4x^2-3/2x+1/4#? How do you find an equation of the parabola with a vertex of (-1,2) and focus of (-1,0)? How do you write the polynomial #4x + x + 2# in standard form and how many terms and degree is it? How do you write the polynomial #1 - 2s + 5s^4# in standard form and how many terms and degree is ... See all questions in Standard Form of the Equation Impact of this question 163 views around the world You can reuse this answer Creative Commons License