How do you use an addition or subtraction formula to find the exact value of #sin((19/12)π)#?
1 Answer
Jun 5, 2015
Use the trig unit circle as proof:
#sin ((19pi)/12) = sin ((7pi)/12 + 2pi) = sin ((7pi)/12) = sin (pi/12 + pi/2) =
cos ((pi)/12) = 0.966#