How do you use cross products to solve #2/9=c/27#?

3 Answers
Apr 16, 2018

Answer:

Just arrange the equation

Explanation:

#2/9 = c/27#

#2times27 = ctimes9#

#(2times27)/9 = c#

#2times3=c#

#6=c#

Answer:

c = 6

Explanation:

First we need to cross multiply.
#2 xx 27 = 9 xx c#

Which gives us...
#54 = 9c#

To make the next step easy, we will flip the equation
#9c = 54#

Now we can find the value of c
#c = 54 / 9#

#c = 6#

Apr 16, 2018

Answer:

#c=6#

Explanation:

#"given equal fractions then we can solve using "color(blue)"cross-products"#

#"that is "a/b=c/drArrbc=adlarrcolor(blue)"cross-products"#

#"applying this to "2/9=c/27" gives"#

#9c=2xx27#

#rArr9c=54#

#"divide both sides by 9"#

#(cancel(9) c)/cancel(9)=54/9#

#rArrc=6#