# How do you use laws of exponents to simplify (3a^4)^3?

$27 {a}^{12}$
Just use the properties ${\left(x y\right)}^{n} = {x}^{n} \cdot {y}^{n}$ and ${\left({x}^{m}\right)}^{n} = {x}^{m \cdot n}$:
${\left(3 {a}^{4}\right)}^{3} = {3}^{3} \cdot {\left({a}^{4}\right)}^{3} = 27 \cdot {a}^{4 \cdot 3} = 27 {a}^{12}$