# How do you use laws of exponents to simplify x^(3a) * x^(4a)?

You get: ${x}^{7 a}$
${x}^{a} \cdot {x}^{b} = {x}^{a + b}$
${x}^{3 a} \cdot {x}^{4 a} = {x}^{3 a + 4 a} = {x}^{7 a}$