# How do you use laws of exponents to simplify y^(2a) * y^3 * y^(3a+1)?

Aug 3, 2015

I got: ${y}^{5 a + 4}$

#### Explanation:

Remember that you have:
${y}^{a} \cdot {y}^{b} = {y}^{a + b}$

for example if you have:
${2}^{2} \cdot {2}^{3} = {2}^{2 + 3} = {2}^{5} = 32$
in fact:
${2}^{2} = 4$
${2}^{3} = 8$ and
$4 \cdot 8 = 32$!!!
So, in your case you have:
${y}^{2 a + 3 + 3 a + 1} = {y}^{5 a + 4}$