How do you use long division to divide $(x^4+5x^3+6x^2-x-2)div(x+2)$ ?

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Answer 1 · 2017-01-28T06:45:28

The answer is $=color(blue)(x^3+3x^2-1)$

Let's do the long division

$color(white)(aaaa)$ $x^4+5x^3+6x^2-x-2$ $color(white)(aaaa)$ $||$ $color(red)(x+2)$

$color(white)(aaaa)$ $x^4+2x^3$ $color(white)(aaaaaaaaaaaaaaaa)$ $||$ $color(blue)(x^3+3x^2-1)$

$color(white)(aaaaa)$ $0+3x^3+6x^2$

$color(white)(aaaaaaa)$ $+3x^3+6x^2$

$color(white)(aaaaaaaaaa)$ $+0+0-x-2$

$color(white)(aaaaaaaaaaaaaaaaa)$ $-x-2$

$color(white)(aaaaaaaaaaaaaaaaa)$ $-0-0$

The quotient is $=color(blue)(x^3+3x^2-1)$

How do you use long division to divide (x^4+5x^3+6x^2-x-2)div(x+2)(x^4+5x^3+6x^2-x-2)div(x+2)?