# How do you use partial fraction decomposition to decompose the fraction to integrate (2x-82)/(x^2+2x-48) ?

$\frac{d}{\mathrm{dx}} \left({x}^{2} + 2 x - 48\right) = 2 x + 2$
$\frac{2 x - 82}{{x}^{2} + 2 x - 48} = \frac{2 x + 2 - 84}{{x}^{2} + 2 x - 48}$
(2x-82)/(x^2+2x-48) = (2x+2)/(x^2+2x-48)-(84)/(x^2+2x-48