Question

How do you use quadratic formula to solve `3x^2-8=0`?

Answer 1

Consider your equation in the general form `ax^2-bx+c=0`
Where you have:
`a=3`
`b=0`
`c=-8`
Now you can apply the quadratic formula:
`x_(1,2)=(-b+-sqrt(b^2-4ac))/(2a)`
Try by yourself: you should get two results. If you do not get them look at the solution below:
.
.
.
.
.
.
Solution:
`x_1=sqrt(96)/6=1.633`
`x_2=-sqrt(96)/6=-1.633`