How do you use solve $x^{2} + 15 x + 50 = 0$ $x^2 + 15x + 50 = 0$ ?

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Answer 1 · 2018-03-08T16:44:37

Break the trinomial into two binomials and solve for x in each of the binomials

$x^{2} + 15 x + 50 = (x + 5) \times (x + 10)$ $x^2 + 15x + 50 = ( x +5)xx( x +10 )$ so

$(x + 5) \times (x + 10) = 0$ $(x + 5) xx ( x +10 ) = 0$

$x + 5 = 0$ $x + 5 = 0$ subtract 5 from both sides

$x + 5 - 5 = 0 - 5$ $x + 5 - 5 = 0 -5$

$x = 5$ $x = 5$

$x + 10 = 0$ $x + 10 = 0$ subtract 10 from both sides

$x + 10 - 10 = 0 - 10$ $x + 10 -10 = 0-10$

$x = - 10$ $x = -10$

The values for x are -5.-10

How do you use solve x^2 + 15x + 50 = 0x2+15x+50=0x^2 + 15x + 50 = 0?