# How do you use solve x^2 + 15x + 50 = 0?

Mar 8, 2018

Break the trinomial into two binomials and solve for x in each of the binomials

#### Explanation:

${x}^{2} + 15 x + 50 = \left(x + 5\right) \times \left(x + 10\right)$ so

$\left(x + 5\right) \times \left(x + 10\right) = 0$

$x + 5 = 0$ subtract 5 from both sides

$x + 5 - 5 = 0 - 5$

$x = 5$

$x + 10 = 0$ subtract 10 from both sides

$x + 10 - 10 = 0 - 10$

$x = - 10$

The values for x are -5.-10