# How do you use the amplitude and period to graph y= .5 cos^-1 (x-(pi/2))?

Jun 25, 2016

Inversely, $x = \frac{\pi}{2} + \cos \left(2 y\right)$.
Amplitude is 1 and period is $\pi$. The axis of the wave is along $x = \frac{\pi}{2}$.
$\left(x , y\right) : \left(\frac{\pi}{2} + 1 , 0\right) \left(\frac{\pi}{2} + \frac{1}{\sqrt{2}} , \frac{\pi}{8}\right) \left(\frac{\pi}{2} , \frac{\pi}{4}\right)$
 (pi/2-1/sqrt 2, (3pi)/8) ((pi/2-1, pi/2) (pi/2-1/sqrt 2, (5pi)/8) ((pi/2+1, pi)-