Question

How do you use the amplitude and period to graph `y= .5 cos^-1 (x-(pi/2))`?

Answer 1

Inversely, `x=pi/2+cos (2y)`.
Amplitude is 1 and period is `pi`. The axis of the wave is along `x = pi/2`.

Explanation:

Data for one full wave:

`(x, y): (pi/2+1, 0) (pi/2+1/sqrt 2, pi/8) (pi/2, pi/4)`

`(pi/2-1/sqrt 2, (3pi)/8) ((pi/2-1, pi/2) (pi/2-1/sqrt 2, (5pi)/8) ((pi/2+1, pi)`-