How do you use the binomial #(2t-s)^5# using Pascal's triangle?

1 Answer
Jul 10, 2017

Answer:

#(2t-s)^5=32 t^5-80st^4 +80s^2t^3- 40t^2s^3+ 10ts^4 -s^5#

Explanation:

Pascal's triangle:

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The sixth row, which corresponds to a binomial raised to the fifth power, shows us the coefficient of each term of that expansion. So the first term has coefficient #1#, the second term #6#, etc.

We also know that, for a binomial raised to #n#, one nomial in each term will have decreasing exponents from #n# to #0# and the other nomial will have increasing exponents from #0# to #n#.

#therefore(2t-s)^5=1(2t)^5(-s)^0+6(2t)^4(-s)^1+10(2t)^3(-s)^2+10(2t)^2(-s)^3+6(2t)^1(-s)^4+1(2t)^0(-s)^5#
#=32 t^5-80st^4 +80s^2t^3- 40t^2s^3+ 10ts^4 -s^5#