How do you use the chain rule to differentiate #sqrt(4x+9)#?
1 Answer
Aug 7, 2017
Explanation:
We're asked to find the derivative
#d/(dx) [sqrt(4x+9)]#
using the chain rule, which here is
#d/(dx) [sqrt(4x+9)] = d/(du)[sqrtu] (du)/(dx)#
where
-
#u = 4x+9# -
#d/(dx)[sqrtu] = 1/(2sqrt(x))# :
#= 1/(2sqrt(4x+9)) d/(dx)[4x+9]#
The derivative of
#= 4/(2sqrt(4x+9))#
#= color(blue)(ulbar(|stackrel(" ")(" "2/(sqrt(4x+9))" ")|)#
