How do you use the chain rule to differentiate #y=4/(sqrt(x-5)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Anjali G Nov 13, 2016 #y=4/(sqrt(x-5))# We can rewrite this as: #y=4(x-5)^(-1/2)# Use the chain rule: #y'=4(-1/2)(x-5)^(-3/2)(1)# #y'=-2(x-5)^(-3/2)# #y'=(-2)/(x-5)^(3/2)# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1374 views around the world You can reuse this answer Creative Commons License