How do you use the chain rule to differentiate y=4(x^3+1)^(1/2)?
1 Answer
Sep 8, 2016
Explanation:
differentiate using the
color(blue)"chain rule"
color(orange)"Reminder " color(red)(bar(ul(|color(white)(a/a)color(black)(dy/dx=(dy)/(du)xx(du)/(dx))color(white)(a/a)|))).... (A)
let
and
y=4u^(1/2)rArr(dy)/(du)=2u^(-1/2) substitute these values into (A) and change u into terms of x.
dy/dx=2u^(-1/2)xx3x^2=(6x^2)/(x^3+1)^(1/2)