Question

How do you use the chain rule to differentiate `y=(x^3+3)^5`?

Answer 1

`dy/dx=5(x^3+3)^4(3x^2)`

Explanation:

Let `y=u^n(x)`
So `dy/dx=n*u^(n-1)(x)*u'(x)`
so applying this
`dy/dx=5(x^3+3)^4(3x^2)`