How do you use the distributive property to rewrite and evaluate #9*99#?

2 Answers
Mar 14, 2017

Answer:

See the solution process for this problem below:

Explanation:

We can rewrite this expression as:

#(9 * 1)(9 * 11) = (9 * 9)(1* 11) = 81 * 11 = 891#

Mar 14, 2017

#(1): 9*99=9(100-1)=900-9=891.#

#(2): 9*99=(10-1)99=990-99=891.#

#(3): 9*99=(10-1)(100-1)=10(100-1)-1(100-1)#

#=1000-10-100+1=990-100+1=890+1=891.#