How do you use the distributive property to rewrite and evaluate $9*99$ ?

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Answer 1 · 2017-03-14T14:22:23

See the solution process for this problem below:

We can rewrite this expression as:

$(9 * 1)(9 * 11) = (9 * 9)(1* 11) = 81 * 11 = 891$

Answer 2 · 2017-03-14T14:31:44

$(1): 9*99=9(100-1)=900-9=891.$

$(2): 9*99=(10-1)99=990-99=891.$

$(3): 9*99=(10-1)(100-1)=10(100-1)-1(100-1)$

$=1000-10-100+1=990-100+1=890+1=891.$

How do you use the distributive property to rewrite and evaluate 9*999*99?